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, when changing r to equal 0.69*i, I said "this is what we might think of as (2i)^x", but that is not correct. It's what we'd think of as [Exp(ln(2)*i)]^x for whatever complex number Exp(ln(2)*i) is.
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Intuition for i to the Power i - Lockdown Live Math
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- 1 , when changing r to equal 0.69*i, I said "this is what we might think of as (2i)^x", but that is not correct. It's what we'd think of as [Exp(ln(2)*i)]^x for whatever complex number Exp(ln(2)*i) is.
- 2 Exponential function for i^i
- 3 Question 1
- 4 Plug-in imaginary number in exp(x) polynomial
- 5 Answer 1 and explanation
- 6 What it really means i^i?
- 7 e^it as a position vector
- 8 Question 2
- 9 Audience question from twitter
- 10 Answer 2
- 11 Where you get after traveling π/2 units of time for position vector e^it
- 12 Question 3
- 13 Audience tweets
- 14 Answer 3
- 15 Question 4
- 16 Answer 4
- 17 How exp(rx) or b^x really works?
- 18 Question 5
- 19 Audience tweets
- 20 Answer 5
- 21 Visualization of f(x)= exp(r*x) i.e. e^(r*x), where r= unique complex number
- 22 Questions to think about
- 23 Audience tweets
- 24 Power tower for i
